Question

WILL FAN AND GIVE MEDAL AND TESTIMONY!!!
An SRS of 16 Spokane County Schools' seniors had a mean SAT Verbal score of 500 with a standard deviation of s = 100. We know that the population is normally distributed. We wish to determine a 90% confidence interval for the mean SAT Verbal score µ for the population of all seniors in the district.

Answer 1

a. Using the above data, the critical value has how many degrees of freedom?
b. What is the critical value for the 90% confidence interval?
c. Find the 90% confidence interval.
d. Suppose the population of all high school seniors has a mean score of 450. We wish to see if the data provide evidence that the mean score of seniors is larger than 450. Write the hypotheses for this test.
e. Carry out the appropriate test of significance at the 5% level and write your conclusions.

Answer 2

@amistre64 @kropot72 @mtbender74

Answer 3

@Sepeario

Answer 4

Do any of you know how to do this?

Answer 5

I know how to do it but it is hard to explain

Answer 6

can you try??

Here is the work I have done so far

Answer 7

a)
b)
c) For 90% CI => z = 1.645
90% CI: μ ± 1.645(σ/√n)
500 ± 1.645(100/√16)
500 ± 1.645(25)
500 ± 41.1...
90% CI (458.9, 541.1) (4s.f.)
d)
e) At a 5 percent significance level, the critical value (for one tailed test) is 1.645. Here, n= 16, so sqrt is 4. (100 / 4 = 25)

Answer 8

one sec

Answer 9

e is correct

Answer 10

ok

Answer 11

I will Brb

Answer 12

ok

Answer 13

A, degrees of freedom, define it for me. what test statistic (ts) does it usually relate to?

B, since the ts is dealing with a degree of freedom, theres a table for it in your material. How do we use that table? if not a table, then what would you use?

C is wrong since you used a ts that is not related to a degree of freedom.

D, what would you say is being claimed? whats a good counter claim to it?

E is wrong since for the same reason as C, you used the wrong ts.