If p varies directly with q, and p = 10 when q = 2, what is the value of p when q = 20? A. p = 1 B. p = 40 C. p = 100 D. p = 28
@igreen @answermyquestions @lordhelix8th @BloomLocke367
you can write a proportion.
\(\Huge\frac{10}{2}=\frac{?}{20}\)
yea we need the poportion
direct variation, has the equation: \(\large\color{black}{ \displaystyle y=\color{orangered}{\rm k}x }\) In this case, though, your variables are \(p\) and \(q\). \(\large\color{black}{ \displaystyle p=\color{orangered}{\rm k}q }\) you are given that \(p=10\) when \(q=2\) AND you can use this information to solve for \(\large\color{black}{ \displaystyle \color{orangered}{\rm k} }\).
that works too ^^
your is definitely shorter:)
10 / 20 = 0.5
cross multiply to solve for the question mark (which you can denote as x)
i used bloomlockes
i figured:)
you have to multiply \(\Huge 10\times 20\) then divide that by \(\Huge 2\)
100
\(\Huge\color{lime}{Correct~\checkmark}\)
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