Question

Fill in Blank

Answer 1

@oldrin.bataku You there?

Answer 2

a is negative and the amp number is 4
so a is?

Answer 3

and hint for b
the period of y=asin(bt) is 2pi/b
and you are given the period is pi/4
so solve pi/4=2pi/b for b

Answer 4

Can you graph it for me @freckles Please

Answer 5

yes I can graph it
but I want to help you graph it

Answer 6

have you found a and b yet?

Answer 7

So a is 4

Answer 8

well remember a is negative

Answer 9

we were told a<0

Answer 10

Ok

Answer 11

would it be -4 sin 8 theta

Answer 12

\[f(t)=-4 \sin(8t)\]
yes sounds great to me
which has amp=|-4|=4
and period 2pi/8 reducing gives pi/4 :)




so y=sin(t) on [0,2pi] looks like this:


but if we put a - in front of the sin(x) then we have to flip our graph about the x-axis
so if we have y=-sin(t) on [0,2pi] that looks like:


so our "important values" for our graph will occur in a the same order as y=-sin(x)
like except everything will be multiplied by 4

so if we wanted to graph y=-4 sin(t) that would look like:


now for y=-4sin(8t) we are going to have a more squished graph with the same design as y=-4sin(t) just more squished since we are trying to fit that one cycle between 0 and pi/4