5. Explain the rate equation including order and overall order of reaction.

Question

anonymous · Answer

@JFraser

jfraser · Answer

have you got a generalized rate equation to look at?

anonymous · Answer

oh yes sorry hold on one moment I'll try to use the equation thing to show you

anonymous · Answer

$$C _{2}H _{6}O(1) +H _{2}(g)\rightarrow C _{2}H _{6}(g) + H _{2}O(g)$$

jfraser · Answer

ok, this is the chemical reaction, but what about a sample rate law equation to look at?

anonymous · Answer

that's actually the equation to a different question I have ugh oops the question I asked didn't provide a equation =/

jfraser · Answer

ok, but in general rate law equations always look the same sort of way

jfraser · Answer

$rate = k*[reactant \space1]^m*[reactant \space 2]^n * (...)$

anonymous · Answer

ok so I can basically explain that order then? saying " rate equals the product of k and the reactants involved" ?

jfraser · Answer

yes, but each reactant has its own order, which is NOT the same as the coefficients from the balanced reaction

anonymous · Answer

ok so the product of k and reactants based off of their individual orders

jfraser · Answer

basically, yes

anonymous · Answer

ok, thank you! I took one semester of chemistry but apparently he lost some of our work so i'm trying to remember =/

anonymous · Answer

@ my next question was about the equation I accidentally typed earlier but it won't let me copy and paste on to a new thread would you mind helping with it on this thread? =o @JFraser