Simplify. Be sure to state the restrictions on the variables. \[\frac{u^2-4}{(u-6)(u-2)}=\frac{u+2}{u-6}\]
you canceled out to (u-2)'s right?
As you can see, I have already simplified. I also know that y \(\ne\) 6 but is y \(\ne\) 2 correct, as well?
Oh, yes. (u - 2) was canceled out.
is y u?
Oh! Yeah, sorry. I didn't notice I put two different variables. XD
\[\frac{u^2-4}{(u-6)(u-2)} , u \neq 6 \text{ or } u \neq 2 \\ \] your simplified version will also have those restrictions
you have done everything here
So, two can not be equal to u as well?
yep
As in, they are both correct answers?
Oh, okay! Thanks!
yep we need u to not b 2 or 6 for the simplified version
like those functions will not be equal if you allowed one to have 2 in the domain but not the other if that makes sense
A little confusing, but I think I understand. :D
ok :)
Thank you for your help again. :)
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