Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Simplify. Be sure to state the restrictions on the variables. \[\frac{u^2-4}{(u-6)(u-2)}=\frac{u+2}{u-6}\]

OpenStudy (freckles):

you canceled out to (u-2)'s right?

OpenStudy (anonymous):

As you can see, I have already simplified. I also know that y \(\ne\) 6 but is y \(\ne\) 2 correct, as well?

OpenStudy (anonymous):

Oh, yes. (u - 2) was canceled out.

OpenStudy (freckles):

is y u?

OpenStudy (anonymous):

Oh! Yeah, sorry. I didn't notice I put two different variables. XD

OpenStudy (freckles):

\[\frac{u^2-4}{(u-6)(u-2)} , u \neq 6 \text{ or } u \neq 2 \\ \] your simplified version will also have those restrictions

OpenStudy (freckles):

you have done everything here

OpenStudy (anonymous):

So, two can not be equal to u as well?

OpenStudy (freckles):

yep

OpenStudy (anonymous):

As in, they are both correct answers?

OpenStudy (anonymous):

Oh, okay! Thanks!

OpenStudy (freckles):

yep we need u to not b 2 or 6 for the simplified version

OpenStudy (freckles):

like those functions will not be equal if you allowed one to have 2 in the domain but not the other if that makes sense

OpenStudy (anonymous):

A little confusing, but I think I understand. :D

OpenStudy (freckles):

ok :)

OpenStudy (anonymous):

Thank you for your help again. :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!