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OpenStudy (darkbluechocobo):

Help with Finding the Angle Between Two Lines

OpenStudy (darkbluechocobo):

Find the angle between the following two lines: x − 2y = 5 6x + 2y = 7 (round your answer to the nearest tenth of a degree).

OpenStudy (darkbluechocobo):

What I have so far

OpenStudy (darkbluechocobo):

\[M _{1}=-1/2 M _{2}=-3\]

OpenStudy (darkbluechocobo):

\[\tan ^{-1}(\frac{ -3-1/3 }{ 1+(-3)(-1/2) }\]

OpenStudy (irishboy123):

use vectors and the cross product.

OpenStudy (darkbluechocobo):

\[\tan^{-1}(\frac{ 7/2 }{ 5/2 })\]

OpenStudy (darkbluechocobo):

i meant -1/2 not -1/3 s:

OpenStudy (darkbluechocobo):

54.5 degrees is the angle?

OpenStudy (loser66):

hey, -3-1/3 = -10/3 , not 7/2

OpenStudy (darkbluechocobo):

but i thought it was -3-(-1/2)?

OpenStudy (loser66):

you posted on 7 box above,

OpenStudy (darkbluechocobo):

Yeh I screwed up typing here shoulda been -3-(-1/2) which still isnt 7/2 i messed up

OpenStudy (loser66):

if it is so, you are ok

OpenStudy (darkbluechocobo):

egh not ok s: im lost now

OpenStudy (darkbluechocobo):

i got 45 degrees which isnt to choose from

OpenStudy (loser66):

why? \(tan^{-1} (7/5) = 54.46 \) , it is correct

OpenStudy (darkbluechocobo):

welp no I screwed up some where else. Because answers to choose from: θ≈ 32.4° θ ≈ 51.6° θ≈ 108.1° θ≈ 81.9°

OpenStudy (darkbluechocobo):

so i messed up something along the way

OpenStudy (loser66):

at M1, it is M1= 1/2 not -1/2

OpenStudy (darkbluechocobo):

Ugh i did this with the last one too T_T -1/-2 = 1/2

OpenStudy (freckles):

hey @DarkBlueChocobo sorry I left you I really really wanted to eat my food :p

OpenStudy (darkbluechocobo):

\[\tan^{-1}(\frac { -7/2 }{ -1/2 })\]

OpenStudy (darkbluechocobo):

81.9 degrees

OpenStudy (loser66):

ok, redo, M1= 1/2 M2 = -3 \(tan^{-1}(\dfrac{M_2-M_1}{1+M_1M_2})= tan^{-1}\dfrac{-3-1/2}{1+(-3)(1/2)}\) yup, you got it

OpenStudy (darkbluechocobo):

Man sorry that took so long. I need to remember that if it happens again T_T simple calculation errors

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