CAn someone show me how to do this?

Question

shelby1290 · Answer

This is how you determine the quadrent:
    1.Find the value of a number using its distance and direction from zero. ...
    2.Find opposite numbers on the number line. ...
    3.Locate a point on the coordinate plane. ...
    4.Determine the quadrant of a point. ...
    5.Predict the reflection of a point by changing values.

howard-wolowitz · Answer

alright

zepdrix · Answer

Hey Howard :)

Sine corresponds to your y-coordinate.
If your sine > 0, that means it's positive.
So which two quadrants do you have a positive y-coordinate?

howard-wolowitz · Answer

one and two?

zepdrix · Answer

|dw:1431480812462:dw|yup sounds good!

zepdrix · Answer

tangent is like... slope.
recall that tangent is sine over cosine.
so you can think of it as y/x, slope of a line.
tangent will be negative in these two quadrants,|dw:1431480884720:dw|see how the line slopes downward?

zepdrix · Answer

So you choose the quadrant that meets both of these requirements.

howard-wolowitz · Answer

dude that would be two and four

howard-wolowitz · Answer

its weird because you can only choice one of them and not two

howard-wolowitz · Answer

@mathstudent55

howard-wolowitz · Answer

@phi  can you explain to me how it could only be one answer

howard-wolowitz · Answer

its not going through one quad but two

phi · Answer

are you asking about  sin(t)>0 and tan(t)<0 ?

howard-wolowitz · Answer

yes

phi · Answer

I think of sin as  the "y" value
and the cos as the x value

first draw circle,  and show where the sin(t)>0  (meaning where y is > 0)
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