Question

Quotient in simplest form???

Answer 1

you have to factor a lot

Answer 2

can you factor
x^2-4?
or
x^3+7x^2?
or
x^3-x^2-6x?
or
x^2+4x-21?

Answer 3

How would I factor out the variables and numbers that are raised with power?

Answer 4

hint for the first one:
a difference of squares is what you have
a^2-b^2=(a-b)(a+b)

hint for the second one:
each term of the expression has an x^2 in common

hint for third one:
each term of the expression has an x in common
you may be able to factor it further (I will try to give another hint for it if you need it)


hint for forth one:
actually you can use this hint for third one as well
ax^2+bx+c
find two factors of a*c that have product ac and sum b.

Answer 5

I still can't get close to any of those answers.

Answer 6

\[x^2-4=(x-2)(x+2) \\ x^3+7x^2=x^2(x+7) \\ x^3-x^2-6=x(x^2-x-6)=x(x-3)(x+2) \\ x^2+4x-21=(x+7)(x-3)\]

now all of them are factored for you

Answer 7

can you continue ?

Answer 8

That's exactly what I did, I just don't know how to find the answer within factoring it. @freckles

Answer 9

oh I thought you said you didn't know how to factor anything
\[\frac{(x-2)(x+2)}{x^2(x+7)} \cdot \frac{(x+7)(x-3)}{x(x-3)(x+2)}\]

Answer 10

now just do a lot of cancelling
a/a=1 for example

Answer 11

on its domain of course

Answer 12

(x+2)/(x+2)=?
(x+7)/(x+7)=?
(x-3)/(x-3)=?

Answer 13

X-2/x^3 ??

Answer 14

yes

Answer 15

well actually (x-2)/x^3

Answer 16

which is what I think you meant