Help with projecting vectors
Find the vector that is orthogonal to the projection vector that comprises the sum of two vector components, if v =-i + 2j and w = 3i − j.
(-1*3)+(2*-1) -3+-2 -5
\[\frac{ -5 }{ ||3,-1||^2 }(3,-1)\]
\[\frac{ -5 }{ \sqrt10^2 }=\frac{ -5 }{ 10 }(3,-1)\]
(-3/2, 1/2)
shouldnt you sum the two vectors , v + w , first
I am confused
the wording of the question is a bit confusing
the way i read it, the projection vector is the sum of the components of the two vectors, therefore it is the vector sum of the two given vectors
Yes as was the last time i did one like this with this wording. Find the vector that is orthogonal to the projection vector that comprises the sum of two vector components, if v =-2i + 5j and w = 5i + 4j. The answer was when we found v2
this particular projection vector happens to be the vector sum of v and w
v2?
so we have to v2=v-v1=
can you take a screen shot of a similar problem
v1= (-3/2, 1/2)
http://openstudy.com/users/darkbluechocobo#/updates/554d0976e4b0a15b79cf38e7
very poorly phrased, whoever wrote this question.
badly phrased
I agree
ok so lets assume they mean the projection of v on w
So to find v2 -i + 2j - (-3/2, 1/2) -1-(-3/2) 2-1/2
(1/2 ,3/2)
v2=(1/2 ,3/2) and due to the last question that was like this, this should be the answer
I agree the projection of v on w is -5/sqrt(10) * (3,-1)
what are the multiple choices given
(-3/2, 1/2) or (1/2 ,3/2
ok one moment,
projection (v on w) =v.w / |w|^2 * w v=(-1,2) w = (3,-1) therefore proj (v on w) = -5/10 * ( 3,-1) = ( -3/2, 1/2) now we have a triangle : proj (v on w) + n = v n = proj(v on w) - v n = v - proj (v on w) = (-1,2) - ( -3/2, 1/2) = ( -1 + 3/2, 2 - 1/2) = ( 1/2, 3/2)
I don't understand why they couldn't have just called it v2 like they did in our lesson. S:
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ok so you agree that n = (1/2, 3/2) different books have different notation, the important thing is to understand the idea, then the notation doesn't really matter. (of course there is bad notation and poorly phrased statements).
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