Question

Can someone show me how to do this:

Answer 1

i cant se what it says

Answer 2

When you click on the image zoom in

Answer 3

opposite over hypotenuse is how you find it

Answer 4

\[\sec\theta ~~=~~ \dfrac{1}{\cos\theta} ~~=~~ \dfrac{1}{\dfrac{\text{Adj}}{\text{Hyp}}}~~=~~\dfrac{\text{Hyp}}{\text{Adj}}\]

So \(\sec\theta\) is ratio of Hypotenuse to Adjacent.

Answer 5

Do you know what value of \(c\) is?

Answer 6

no i dont

Answer 7

cos you mean

Answer 8

no, side c.

Answer 9

possibly 10

Answer 10

we know a=b=5

Notice that is 45 45 90 triangle?

Answer 11

Or maybe try use Pythagorean Theorem here?
\[a^2+b^2=c^2\]

Answer 12

hmm ok all I have to do then is get C

Answer 13

kind of, you need to find \(\dfrac{c}{b}\).

But we don't know \(c\). so we need to work on that.

Answer 14

Hyp is c,and Adj is b.

Answer 15

So using Pythagorean Theorem, what is c? @Howard-Wolowitz

Answer 16

2 something

Answer 17

I still dont get the whole C thing

Answer 18

@geerky42 you cant o this without knowing C .. at least I dont think

Answer 19

c^2 = 5^2 + 5^2
c^2 = 50

Answer 20

^