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Mathematics 11 Online
OpenStudy (anonymous):

Suppose a sample of 80 with a sample proportion of 0.58 is taken from a population. Which of the following is the approximate 68% confidence interval for the population parameter? A. (0.525, 0.635) B. (0.470, 0.690) C. (0.359, 0.801) D. (0.414, 0.746)

OpenStudy (amistre64):

what is the midpoints of each interval?

OpenStudy (amistre64):

well, they all have the same midpoint so we cant narrow it by that.

OpenStudy (amistre64):

what is the z score for 68%? and what is the standard error for the sample size?

OpenStudy (anonymous):

its a complicated way to to do it and i don't have the right calculator for it

OpenStudy (amistre64):

it can be done on a basic calculator, something with a square root

OpenStudy (amistre64):

tell me the formula for the standard error

OpenStudy (amistre64):

the approximation means that we will use the emipirical rule, maybe you know it as the 68-95-99 rule?

OpenStudy (anonymous):

i just seen that

OpenStudy (amistre64):

we should still know how to calculate for a standard error. once we know that this is pretty well answered.

OpenStudy (amistre64):

thats just a picture of a dot ...

OpenStudy (anonymous):

it wont let me put the picture

OpenStudy (amistre64):

use your words ... type with your fingers

OpenStudy (anonymous):

p+\[p \pm 1\times \sqrt{p(1-p)/n}\]

OpenStudy (amistre64):

very good lets just use one endpoint since all the solutons differ. what is .58(.42)/80?

OpenStudy (anonymous):

0.003045

OpenStudy (amistre64):

now take the square root of that

OpenStudy (anonymous):

0.05518151864528558

OpenStudy (amistre64):

you do know where i got the values for p and n right? now add that to .58

OpenStudy (amistre64):

we only need 3 decimals so .055 + .58 is our upper limit

OpenStudy (anonymous):

0.635

OpenStudy (amistre64):

then lets pick that one

OpenStudy (amistre64):

i take it your done with this one ....

OpenStudy (amistre64):

good luck

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