Suppose a sample of 80 with a sample proportion of 0.58 is taken from a population. Which of the following is the approximate 68% confidence interval for the population parameter? A. (0.525, 0.635) B. (0.470, 0.690) C. (0.359, 0.801) D. (0.414, 0.746)
what is the midpoints of each interval?
well, they all have the same midpoint so we cant narrow it by that.
what is the z score for 68%? and what is the standard error for the sample size?
its a complicated way to to do it and i don't have the right calculator for it
it can be done on a basic calculator, something with a square root
tell me the formula for the standard error
the approximation means that we will use the emipirical rule, maybe you know it as the 68-95-99 rule?
i just seen that
we should still know how to calculate for a standard error. once we know that this is pretty well answered.
thats just a picture of a dot ...
it wont let me put the picture
use your words ... type with your fingers
p+\[p \pm 1\times \sqrt{p(1-p)/n}\]
very good lets just use one endpoint since all the solutons differ. what is .58(.42)/80?
0.003045
now take the square root of that
0.05518151864528558
you do know where i got the values for p and n right? now add that to .58
we only need 3 decimals so .055 + .58 is our upper limit
0.635
then lets pick that one
i take it your done with this one ....
good luck
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