Trouble with trigonometry, please help!

Question

anonymous · Answer

Freddie is at chess practice waiting on his opponent's next move. He notices that the 4-inch-long minute hand is rotating around the clock and marking off time like degrees on a unit circle.

anonymous · Answer

Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches?
Part 4: What is the coordinate point associated with this radian measure?

anonymous · Answer

For part 3:
1 pi = 180 degrees so 3pi will equal 540 degrees

anonymous · Answer

Not really sure how part 3 works

jdoe0001 · Answer

hmmm the clock is moving clockwise obviously

babynini · Answer

I think they want the answer in radian for part 3, not degrees, correct? o.0

anonymous · Answer

Yes

anonymous · Answer

For some reason I get that the answer would be 3pi radians

jdoe0001 · Answer

hmmm that came out... a bit off   anyhow

though the wording on part 3 is very poor

what they really mean is
what's the angle in radians, if the "arc" were to be 3πin long

jdoe0001 · Answer

well.. that's a reasonable assumption,
since the arc's length is given in $\pi$ terms

however   is just what I meant by poor wording of it
$\bf s=r\theta\impliedby \textit{angle in radians}\quad 
\begin{cases}
r=4\
s=3\pi 
\end{cases}
\ \quad \
s=r\theta\implies 3\pi =4\theta\implies \cfrac{3\pi }{4}=\theta$

babynini · Answer

ai! no no sorry, the clock moves clockwise.

anonymous · Answer

This was what I had at first but wasn't sure
l = r(theta)
3pi = 4(theta) 
3pi / 4 = theta

anonymous · Answer

so the same thing that you have I believe

jdoe0001 · Answer

yeap

jdoe0001 · Answer

so  move that much, CLOCKWISE, and you'd get the spot the minute hand is at :)

anonymous · Answer

Ok we verified that, what about part 4? I was getting $$(\sqrt[-2]{2},\sqrt[2]{2})$$

jdoe0001 · Answer

well..    more like  $\bf \left( -\cfrac{\sqrt{2}}{2}, -\cfrac{\sqrt{2}}{2}\right)$

jdoe0001 · Answer

or 7:30

anonymous · Answer

how do you write it big like that

jdoe0001 · Answer

big?    you can just right-click it and see it :)

anonymous · Answer

I mean look at the size of my coordinate versus yours, anyways are they the same thing?

jdoe0001 · Answer

well.. your is missing the rational part

anonymous · Answer

ok and are they both supposed to be negative or one is positive?

jdoe0001 · Answer

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