Question

What is the equation of the line, in slope-intercept form, that passes through (4, 2) and (-2, -3)?

5x - 6y - 8 = 0
3y = -2x + 20
y=5/6x-4/3


What is the equation of the line, in general form, that passes through the point (-1, -1) and is parallel to the line whose equation is x + y = 3?


x - y + 2 = 0
x + y + 2 = 0
x + y - 2 = 0

Answer 1

That is geometry dude

Answer 2

It's in my Algebra 1

Answer 3

Let me see, im learning this now, I'll try to help u

Answer 4

Ok, awesome!

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 2}})\quad
% (c,d)
&({\color{red}{ -2}}\quad ,&{\color{blue}{ -3}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\
% point-slope intercept
y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 6

for the 2nd one
solve first -> x + y = 3 <- for "y", see what you end up with