Question

Need help with simplifying this:
(3m + n) / (n - 1) * (n^2 - n)/5

Answer 1

\[\frac{3m+n}{n-1} \cdot \frac{n^2-n}{5}\]
I would suggest factoring the (n^2-n)

Answer 2

after you factor n^2-n
you should see a common factor and top and bottom

Answer 3

n * (n - 1)?

Answer 4

\(\bf \cfrac{3m+n}{n-1} \cdot \cfrac{n^2-n}{5}\implies \cfrac{3m+n}{\cancel{n-1}} \cdot \cfrac{n\cancel{(n-1)}}{5}\)

Answer 5

Ah, okay. So, the final result is 3m+n/5. Thank you, freckles and jdoe.

Answer 6

Thanks for giving freckles a medal, jdoe. :-)

Answer 7

well \(\bf \cfrac{3m+n}{\cancel{n-1}} \cdot \cfrac{n\cancel{(n-1)}}{5}\implies \cfrac{(3m+n)n}{5}\implies \cfrac{3mn+n^2}{5}\)