Question

Please help guide me through this... fan and medals! What is the solution to the system of equations represented by the two equations?
y=-2x + 7
y=1/3x

Answer 1

@dan815 @mathmath333 can you help?

Answer 2

hint: \(\large {
\begin{array}{llll}
{\color{brown}{ y}}=-2x + 7\\
{\color{brown}{ y}}=\frac{1}{3}x
\end{array}\qquad {\color{brown}{ y}}={\color{brown}{ y}}\qquad -2x + 7=\frac{1}{3}x}\)

solve for "x"

Answer 3

once you get "x", use that on either equation, to get "y:

Answer 4

I'm not sure how to combine 1/3x and -2x here...

Answer 5

Because wouldn't you add -2x - 1/3x +7?

Answer 6

@jdoe0001

Answer 7

well. youd' want to multiply both sides by 3 first
then simplify to get "x"

Answer 8

So -2x times 3 +7 = 1/3x times 3?

Answer 9

Then add like terms?

Answer 10

well \(\bf 3\cdot 2x + 3\cdot 7=\cancel{3}\cfrac{1}{\cancel{3}}x\implies 6x+21=x\)

Answer 11

hmm actually should be -2x so

Answer 12

-6x?

Answer 13

\(\bf 3\cdot -2x + 3\cdot 7=\cancel{3}\cfrac{1}{\cancel{3}}x\implies -6x+21=x\)
yeap

Answer 14

so... now would you divide by -6 for both sides?

Answer 15

nope add +6x to both sides
then divide by 7

Answer 16

So... 3=x?

Answer 17

\(\bf \cancel{-6x+6x}+21=+6x+x\implies 21=7x\implies \cfrac{21}{7}=x\implies x=3\)

yeap

Answer 18

so now we know x = 3
so
in " y=-2x + 7"

x = 3
thus

y=-2(3) + 7
y = -6+7
y = 1

Answer 19

So of the other one, y=1/3(3)?

Answer 20

So, (1,1) is my answer

Answer 21

doesn't matter
you could do the other if you wish
BUT

the other one will give the same

but yes \(\bf y=\cfrac{1}{\cancel{3}}\cancel{3}\)

Answer 22

well. recall (x,y)

x = 3 and y = 1
thus -> (3,1)

Answer 23

Oh, duh of course xP.

Answer 24

Thank you so much!!!!