Given a dataset of n ordered pairs (each an (x,y)), how many degrees of freedom are there?
@amistre64 @kropot72 @jtvatsim @sdfgsdfgs
depends on the course
AP Statistics
its not standardized. i meant its specific to your course. it should be in your material. i can take a guess at it but it would in no manner be considered correct
given a data set in (x) we have 1 degree of freedom its 1 dimensional by extension, (x,y) is 2 dimensional
Yeah... my lessons in my course are terrible and in this one the link is a video that is no longer working so I have been winging it off of stattrek.com
I found (n-2)
the side effects of having a democrat in office ....
in some courses its (x-1) + (y-1) or (x+y) - 2 in other courses its the smaller of x or y, -1
in others they take an average of x and y
ok. Yeah, it's a little frustrating
in others theres a more complicate formula ... its course dependant
ok. Well, thank you for taking a look at it and trying :)
if the ordered pairs are independant, one does not effect the other, then i would conclude that we have 2 degrees of freedom but if x affects the choice for y, then we only have one degree of freedom ... say x + y = 6 we are free to choose x, say 2. but the value of x doesnt give us any freedom to choose y now, y has to be 4 if we have a function of 2 independant variables, f(x,y) then we are free to choose x and y, 2 degrees of freedom but if y = g(x) the f(x,g(x)) only really has 1 degree of freesom how this relates to your question tho is beyond me
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