Just two hard questions:
pufff dislike lengthy problems
would you like help with the first one
yes please
alright i gotcha so far
chair A requires 1 hour of waxing chair B requires 4 hours of waxing The maximum number of hours available (per week) for waxing is 100 hours. If x = number of chair A produced, y = number of chair B produced, we have: 1x + 4y <= 100 Similarly chair A requires 5 hour of painting chair B requires 6 hours of painting The maximum number of hours available (per week) for painting is 60 hours. If x = number of chair A produced, y = number of chair B produced, we have: 5x + 6y <= 60
alright im still with u
srry i had tot think.. but i am still with u
ok that should be enough information to pick the correct answer
you mean 2y
oops, typo
ok the first one is C .. awesome
we got that one on LOCK DOWN
The cost per chair A is 0.79 The total cost to produce chair A is 0.79 * x The cost per chair B is 2.00 The total cost to produce chair B is 2.00 * y total cost to produce both chairs = .79x + 2y Total cost cannot exceed 50. 0.79x + 2y <= 50
i gotcha
no worries
for the next one, i dont see an easy to do it, except by trial and error
alright i can try that
hmm i didnt do it right
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