Question

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

Use the equation:
\[\Delta T\ =\ k _{f}m\]
where \[k_{f}\] is the freezing point depression constant and m is the molality of the solution (moles solute divided by kg of solvent)