The water level varies from 12 inches at low tide to 52 inches at high tide. Low tide occurs at 9:15 a.m. and high tide occurs at 3:30 p.m. What is a cosine function that models the variation in inches above and below the water level as a function of time in hours since 9:15 a.m.?
@phi @amistre64 @Preetha
@rational @SolomonZelman @Preetha @confluxepic
Can one of you help?
start with cosine function and adjust it
how? @amistre64
what does the information tell us?
or rather, what are the parts of a cosine function? how do we write a generic cosine function?
that the min is 12 and the max is 52, right?
good, and the midline is between them
what is the distance from 12 to 52?
strategy define the most general generic cosine function there is. use the information in the problem to build that function into the perfect model of the problem.
the distance is 40, so the amplitude is 20
@amistre64
using words instead of letters, the generic cos function is Amp cos(per(t-phase)) + mid you found amp, what is midline?
and the most generic cosine function is y=cos(x), right?
no, cos(x) is too specific, there are many more parts to a trig function then x
what do you mean?
i mean what i said
a completly generic cosine function is: Amp cos(per(t-phase)) + mid why????
what's (t-phase)?
t is the independant input, and phase is the shifting of the function left or right
do all cosine function have the value cos(0) = 1?
yes?
really cos(t-pi/2), when t = 0 is equal to 1?
might have misasked the first time.
can functions be shifted left and right?
yes, they can be
how do we shift a function f(x) ?? what gets adjusted?
it depends on the function, right? like a quadratic function shifts if the vertex changes
it doesnt depend on the function, if it did then we could never generalize it. f(x) shifts left and right by adjust the value of x by some constant f(x-a) shifts the function to the right by a, why? let f(x) = k when x=0 f(x-a) = k when x=a x is shifted to the right by a
x^2 + 1 = 1, when x=0 (x-4)^2 + 1 = 1 , when x=4 (x-4)^2 + 1 is the same function as x^2+1 shifted by +4
cos(t) = 0 when t = pi/2 cos(t - pi/4) = 0 when t = pi/2 + pi/4 ^^^^^^ notice that the function is shifted to the right, by pi/4
okay
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