Question

I need help with this problem:


A 12-member committee is going to choose a chairman, vice-chairman, and secretary.


In how many ways can these people be chosen?

A.
36 ways

B.
1320 ways

C.
1728 ways

D.
79,833,600 ways

Answer 1

For the first job they choose, there are 12 possibilities.
For the second, there are only 11 left.
For the third, there are but 10 left.
To find the permutations, multiply all the possibilities so that each combination is counted.

\[Permutations = 12 \times 11 \times 10 = your~answer\]