Quick question (I just want someone to check my answer)
If the standard form of a parabola with a vertex (h,k) is (x-h)^2 = 4p(y-k) then simplify this equation into standard form: x^2 +2x-y+3=0

Question

Quick question (I just want someone to check my answer)
If the standard form of a parabola with a vertex (h,k) is (x-h)^2 = 4p(y-k) then simplify this equation into standard form: x^2 +2x-y+3=0

jamierox4ev3r · Answer

If I'm correct, this is a problem on completing the square

jamierox4ev3r · Answer

so this is what I've done so far:

$$x ^{2}+2x-y+3=0$$
$x^{2}+2x+1=y-3+1$
this then becomes:

$(x-1)^{2}$ = $1(y-2)$

jamierox4ev3r · Answer

Is this literally all i need to do? o3o

jamierox4ev3r · Answer

@sleepyjess  @e.mccormick

anonymous · Answer

a bit correction.. it should be x+1
 and to look it more standard write it as (x+1)^2 = 4*1/4(y-2)

jamierox4ev3r · Answer

oops yeah i had addition instead of subtraction, that was just a typo. My mistake.

jamierox4ev3r · Answer

And oh i see why you would make those additions, since p is muliplied by 4...are they really necessary additions though? @divu.mkr ?

anonymous · Answer

yep