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Mathematics 20 Online
OpenStudy (jessicawade):

math help and trig stuff

OpenStudy (jessicawade):

@Michele_Laino

OpenStudy (jessicawade):

21. Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) > 0, tan (t) > 0. Quadrant IV Quadrant I Quadrant II Quadrant III

OpenStudy (jessicawade):

oh nvm its not triangles i thought it was for some reason

OpenStudy (freckles):

ok remember (x,y)=(cos(theta),sin(theta)) (assume r=1) you are given so for that x is positive and y/x is positive so what does that mean about y?

OpenStudy (freckles):

come on if you divide a positive by a positive you get a ? and if you divide a positive by a negative you get a ? and if you divide a negative by a positive you get a? and if you divide a negative by a negative you get a ?

OpenStudy (michele_laino):

hint: |dw:1431621822633:dw|

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

the first quadrant?

OpenStudy (freckles):

yes since y/x is positive and x is positive then yes y is definitely positive also

OpenStudy (freckles):

so you have (x,y)=(+,+)

OpenStudy (jessicawade):

so its in quadrant 1?

OpenStudy (freckles):

yes is what I said :p

OpenStudy (jessicawade):

hehe sorry

OpenStudy (jessicawade):

ok @freckles and @Michele_Laino \[Given \cot \theta=\frac{ 3 }{ 10 } find \tan \theta\]

OpenStudy (jessicawade):

i tried this and couldn't find it

OpenStudy (jessicawade):

this is the last one

OpenStudy (freckles):

tan and cot are reciprocal functions of one another

OpenStudy (michele_laino):

it is very simple, since we have: \[\tan \theta = \frac{1}{{\cot \theta }} = \frac{1}{{\frac{3}{{10}}}} = 1 \times \frac{{10}}{3} = ...?\] since we have to compute the first fraction by the inverse of the fraction at denominator

OpenStudy (jessicawade):

i got 3.3 lol

OpenStudy (michele_laino):

better is to express the result as a fraction

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