Question

Three questions need help with

Answer 1

@CGGURUMANJUNATH
@Hero
@dan815
@nincompoop
@Michele_Laino

Answer 2

@LegendarySadist can you help me with these questions

Answer 3

I don't know the first and third, but since it says "randomly" in the second, and there's no system or stratified sampling, the second should be random sampling.

Answer 4

ok thanks maybe i can ask another question

Answer 5

what do you think about these

Answer 6

I know 30, but that's the only one. I haven't done these in forever.

Answer 7

what about these

Answer 8

or these

Answer 9

I know completely 32-34 and 35-36

Answer 10

can you help me with them

Answer 11

Sure. So I'll help you with 30, 32, 33, 34, 35, and 36. Sound good?

Answer 12

thanks

Answer 13

For 30, all you really have to do is figure out which two numbers you would multiply to get -81. So one has to be positive and one has to be negative.

Answer 14

-9 and 9

Answer 15

Yep, and the choice that has that is going to be your answer

Answer 16

32 is just the Pythagorean theorem.

Answer 17

32: \[20^2+21^2=c^2\] Just solve for c

Answer 18

33:\[11^2+b^2=61^2\] Just solve for b

Answer 19

29

Answer 20

60

Answer 21

For 32, yep. It was kinda obvious since it was the only choice bigger than the other two.

Answer 22

For 33, yep

Answer 23

34?

Answer 24

34: When you want to get rid of a square root, multiply it by itself. But you have to do it on both sides so\[\frac{ 3 }{ \sqrt{15} }*\frac{ \sqrt{15} }{ \sqrt{15} }\to \frac{ 3*\sqrt{15} }{ \sqrt{15}*\sqrt{15} }\] Can you take it from there?

Answer 25

\[\frac{ 3\sqrt{15} }{ \sqrt{15} }\]

Answer 26

\[\sqrt{15}*\sqrt{15}=\sqrt{15}^2=15\] \[3=\sqrt{9}\to \sqrt{9}*\sqrt{15}=\sqrt{45}\] So it would be \[\frac{ \sqrt{45} }{ 15 }\]

Answer 27

? how did u do the top

Answer 28

The second line I had there, the one above "So it would be"

Answer 29

ok

Answer 30

35 and 36

Answer 31

Actually not so sure about 35. I'm leaning pretty heavily on the "no solutions' answer, but I'm not 100% about it.

Answer 32

what about 36

Answer 33

I'ma do 37 instead.

Answer 34

ok

Answer 35

A bit sloppy, but here it is

Answer 36

Basically you do it like long division.

Answer 37

ok can i ask one more question

Answer 38

Can't help ya there, sorry /:

Answer 39

its ok thanks though

Answer 40

No problem :)