find m angle T http://static.k12.com/eli/bb/817/-1/0/2_37302_44974/-1/b0c7bc40f7e5f494498c3168c8648c065cd7076e/media/1ffbb5452bc7b01f7797bf13360cfec23755f76b/mediaasset_652048_1.png
@LegendarySadist
last one lol @LegendarySadist
This would be law of cosines. Do you know what that is?
adj/hyp
That is what cosine is. I'm talking about the LAW of cosines. Do you know what it is or no?
ohh not really
Well it basically says that \[C^2=A^2+B^2-2(A)(B)\cos(c)\] The C is going to be the length of the side opposite the angle you are looking for and the c is the angle you are looking for.
im still confused can you plug that in and then ill solve @LegendarySadist
so C is 12 and c is T ?? then the rest ?? @LegendarySadist
\[12^2=19^2+22^2-2(19)(22)\cos(c)\] What you have to do is get c alone.
144=845-2(19)(22) cos(c) ok do i multiply 2 by 19 then 2 by 22 then multiply them together ? im stuck here @LegendarySadist
Bring the 845 over by subtracting it on both sides. Multiply 2, 19, and 22 together. Then give me the results of that.
-701=836cos(c) @LegendarySadist
Ok, good. Now divide the 836 over.
-0.84=cos(c) @LegendarySadist
That would be a positive .84. The 836 should have been negative. But you would do the acos of it so\[c=acos(.84)\]
is that the answer @LegendarySadist
Well solve the acos(.84) and you'll get the answer
how do i do that? i dont have it on my calculator @LegendarySadist
acos should look like \[\cos ^{-1}\] on the calculator
32.86 @LegendarySadist
Yep, so the answer is 32.86 degrees.
thank you sooo much for helpingg!!! @LegendarySadist
No problem :)
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