Question

Simplify the trigonometric expression.
sin^2 theta / 1 - cos theta

Answer 1

well use

\[\sin^2(\theta) + \cos^2(\theta) = 1\]

which can be written as

\[\sin^2(\theta) = 1 - \cos^2(\theta)\]

so your question becomes

\[\frac{1 - \cos^2(\theta)}{1 - \cos(\theta)}\]

factor the numerator and you'll see a common factor

Answer 2

so would the answer be 1+ cos theta

Answer 3

@campbell_st ??

Answer 4

\[\frac{u^2-v^2}{u-v}=\frac{(u-v)(u+v)}{u-v} \text{ this step factored a difference of squares } \\ =u+v \text{ this step used } \frac{u-v}{u-v}=1 \text{ assumning of course } u \neq v\]

Answer 5

so yes

Answer 6

it would be... well done

Answer 7

thank you !