Question

Each side of a square loop of wire measures 2.0 cm. A magnetic field of 0.044 T perpendicular to the loop changes to zero in 0.10 s. What average emf is induced in the coil during this change?
(Points : 3)
1.8 V

0.088 V

0.88 V

0.00018 V
I ttink its D

Answer 1

@SolomonZelman @aaronq @RedNeckOutLaw @confluxepic

Answer 2

Faraday's Law:
\[\mathcal {E} = - \frac{d \phi}{dt} = - \frac{d \ (BA)}{dt} = - A \ \frac{dB}{dt}\]
dB/dt = -0.044/0.1
A = (0.02)^2

Answer 3

U know magnetic flux=B.A=BA*cos 0=BA*1=BA

Answer 4

Do u know the angle between B nd A