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The position of an object at time t is given by s(t) = -1 - 13t. Find the instantaneous velocity at t = 8 by finding the derivative @ivancsc1996
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I assume you mean \(s(t)=-1-13t\)? If that's the case, what's the derivative? What's the value of the derivative with \(t=8\)?
The velocity of a particle undergoing one dimensional motion is \(v=\frac{ds}{dt}\). So we fist find the velocity as a function of time. \[v(t)=\frac{ds}{dt}(t)=-13\] So we find that the object is moving with constant velocity (independent of time). Therefore, the answer is -13 at all times (including \(t=8\)).
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