Solve and graph the absolute value inequality: |2x + 4| > 14?
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jimthompson5910 (jim_thompson5910):
Rule: |x| > k breaks into these two inequalities: x > k or x < -k
where k is some positive number
jimthompson5910 (jim_thompson5910):
using that rule
|2x + 4| > 14
will turn into
2x + 4 > 14 or 2x + 4 < -14
jimthompson5910 (jim_thompson5910):
what do you get when you solve 2x + 4 > 14 ?
OpenStudy (anonymous):
where does k come from?
jimthompson5910 (jim_thompson5910):
k is just some constant
it's a placeholder for some positive number (any positive number)
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OpenStudy (anonymous):
6x>14 ?
jimthompson5910 (jim_thompson5910):
examples:
|x| > 3 turns into x > 3 or x < -3
|x| > 12 turns into x > 12 or x < -12
etc etc
jimthompson5910 (jim_thompson5910):
2x +4 doesn't turn into 6x
OpenStudy (anonymous):
Oh okay
jimthompson5910 (jim_thompson5910):
2x and 4 are not common terms. You cannot add them like that
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OpenStudy (anonymous):
so only add like terms
jimthompson5910 (jim_thompson5910):
yes like 2x and 3x
2x+3x = 5x
jimthompson5910 (jim_thompson5910):
how would you isolate x in 2x + 4 > 14
OpenStudy (anonymous):
Oh okay I see
OpenStudy (anonymous):
by getting 4 on the other side
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jimthompson5910 (jim_thompson5910):
how do you do that? what must you do to both sides?
OpenStudy (anonymous):
subtract 4
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
so 2x>10
jimthompson5910 (jim_thompson5910):
correct
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jimthompson5910 (jim_thompson5910):
what's next?
OpenStudy (anonymous):
divide 2 on each side?
jimthompson5910 (jim_thompson5910):
correct, giving you what?
OpenStudy (anonymous):
x>5?
jimthompson5910 (jim_thompson5910):
very good
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jimthompson5910 (jim_thompson5910):
so 2x + 4 > 14 leads to x > 5
jimthompson5910 (jim_thompson5910):
solve 2x + 4 < -14 for x
OpenStudy (anonymous):
Yes, so isnt there another equation
jimthompson5910 (jim_thompson5910):
there is
jimthompson5910 (jim_thompson5910):
inequality actually
not equation
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OpenStudy (anonymous):
Ok 2x+4<-14
then subtract four from each side giving me
2x<-18
then divide 2 on each side leaving me with
x<-9 ??
jimthompson5910 (jim_thompson5910):
the steps and answer are correct
jimthompson5910 (jim_thompson5910):
|2x + 4| > 14
will turn into
2x + 4 > 14 or 2x + 4 < -14
-----------------------
solve 2x+4 > 14 for x to get x > 5
solve 2x+4 < -14 for x to get x < -9
OpenStudy (anonymous):
so then i have to put it on a number line graph
jimthompson5910 (jim_thompson5910):
that means |2x + 4| > 14 has the solution set of x > 5 or x < -9
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OpenStudy (anonymous):
Oh okay, but is < and > a closed or open circle?
jimthompson5910 (jim_thompson5910):
draw out a number line
make sure +5 and -9 are on it
place open circles at +5 and -9
to graph x > 5, you'll shade to the right of the open circle at +5
to graph x < -9, you'll shade to the left of the open circle at -9
jimthompson5910 (jim_thompson5910):
< or > means open circle
\(\Large \le\) or \(\Large \ge\) means closed circle