Mathematics
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OpenStudy (darkbluechocobo):
Help with Hyperbolas
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OpenStudy (darkbluechocobo):
For the following equation, find the foci of the hyperbola:
\[\frac{ (x-1)^2 }{ 9 }-\frac{ (y-5)^2 }{ 25 }=1\]
OpenStudy (darkbluechocobo):
c=sqrt(9^2+25^2)
OpenStudy (anonymous):
Here are some my handy notes for this
OpenStudy (darkbluechocobo):
welp I got c =sqrt704 or aproximately 26.6
OpenStudy (anonymous):
hold on let me work this out because my class never decimals for an answer while we did this
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OpenStudy (anonymous):
never got*
OpenStudy (anonymous):
a^2=9 b^2=25
c^2=a^2+b^2
c^2=9+25
c^2=34
c=\[\sqrt{34}\]
OpenStudy (darkbluechocobo):
Ohh I forgot to square s:
OpenStudy (anonymous):
\[foci =(\sqrt{34},0)\]
OpenStudy (anonymous):
is that an answer choice?
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OpenStudy (darkbluechocobo):
(1+sqrt34,5), (1-sqrt34,5
(1,5 + sqrt34), (1,5 - sqrt34)
(-3, 5), (5, 5)
(5, 5), (-4, 5)
OpenStudy (darkbluechocobo):
(h,k +c), (h,k -c) i believe is what we use for foci so i believe it is B
OpenStudy (anonymous):
hmmm
OpenStudy (anonymous):
I would have to go with be as well
OpenStudy (anonymous):
B i mean answer choice B
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OpenStudy (darkbluechocobo):
Thank you :D
OpenStudy (anonymous):
No problem good to see to you on here again Chocobo!