Mathematics
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OpenStudy (anonymous):
what is the equation of a parabola with focus at F (2,-2) and directrix at y=4
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OpenStudy (anonymous):
@jim_thompson5910 Please help!
OpenStudy (anonymous):
@dan815 help please!
OpenStudy (anonymous):
I need to find the equation
jimthompson5910 (jim_thompson5910):
The y coordinate of the focus is y = -2
how far is y = -2 from y = 4 ?
OpenStudy (anonymous):
6?
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jimthompson5910 (jim_thompson5910):
correct
OpenStudy (anonymous):
y = 1/12 x^2 -1/3x-2/3?
jimthompson5910 (jim_thompson5910):
cut this in half to get 6/2 = 3
the distance from the focus to the vertex is 3 units, so p = 3 (p is the focal distance)
jimthompson5910 (jim_thompson5910):
what is the midpoint of (2,-2) and (2,4) ?
OpenStudy (anonymous):
4?
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jimthompson5910 (jim_thompson5910):
plot the two points (2,-2) and (2,4)
which point is directly in the middle of the two of them?
OpenStudy (anonymous):
2,1?
jimthompson5910 (jim_thompson5910):
that's the vertex
(h,k) = (2,1)
OpenStudy (anonymous):
y = -1/12 x^2 -1/3x-2/3?
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jimthompson5910 (jim_thompson5910):
4p(y-k) = (x-h)^2
4*3(y-1) = (x-2)^2
12(y-1) = (x-2)^2
y-1 = (1/12)*(x-2)^2
y = (1/12)*(x-2)^2+1
jimthompson5910 (jim_thompson5910):
one final adjustment
the parabola opens downward, so the leading coefficient 1/12 needs to be negative
so the actual equation is y = (-1/12)*(x-2)^2+1
jimthompson5910 (jim_thompson5910):
hopefully you can see how I isolated y
OpenStudy (anonymous):
thanks so it is y = -1/12 x^2 +1/3x+2/3?
jimthompson5910 (jim_thompson5910):
yes it is once you expand out y = (-1/12)*(x-2)^2+1
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OpenStudy (anonymous):
thanks can you help with a few more?
jimthompson5910 (jim_thompson5910):
I'll do 2 more
OpenStudy (anonymous):
a parabola has a focus at F(-2,4)and a directrix at y=0. what is the location of the vertex?
OpenStudy (anonymous):
what formula should be used to derive the equation of a parabola given its focus and directrix
OpenStudy (anonymous):
what is the general equation for a parabola with its vertex at the origin?
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jimthompson5910 (jim_thompson5910):
we will use 4p(y-k) = (x-h)^2 again
p = focal distance
(h,k) = vertex
jimthompson5910 (jim_thompson5910):
to find the focal distance, you find the distance from directrix to focus, then you cut that distance in half
jimthompson5910 (jim_thompson5910):
so what is the focal distance?
OpenStudy (anonymous):
-2?
jimthompson5910 (jim_thompson5910):
y = 0 is the directrix
y = 4 is the y coordinate of the focus
what is the change in y?
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OpenStudy (anonymous):
2?
OpenStudy (anonymous):
(-1,4)
jimthompson5910 (jim_thompson5910):
y = 0 to y = 4 is a change of 4
jimthompson5910 (jim_thompson5910):
4-0 = 4
jimthompson5910 (jim_thompson5910):
cut this distance in half
4/2 = 2
so p = 2
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jimthompson5910 (jim_thompson5910):
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jimthompson5910 (jim_thompson5910):
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jimthompson5910 (jim_thompson5910):
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