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Mathematics 11 Online
OpenStudy (darkbluechocobo):

Help with hyperbolas

OpenStudy (darkbluechocobo):

Find the equation of the following hyperbola based on the following information: Vertices: (0, ±2), foci (0, ±4).

OpenStudy (darkbluechocobo):

so is the distance between the center and the vertices are 2 ,and the distance from the vertices to the foci is 2 as well and four from the center so does a = 2?

OpenStudy (darkbluechocobo):

@~Gelmhar

OpenStudy (anonymous):

the a value that you get from vertices is2 , and the c value from foci is 4, by using c^2=a^2+b^2 , you will get the value of b , and place the value of a and b to the standard equation of hyperbola

OpenStudy (darkbluechocobo):

4^2=2^2+b 16=4+b 12=b

OpenStudy (anonymous):

b^2=12

OpenStudy (darkbluechocobo):

ohh so sqrt 12

OpenStudy (darkbluechocobo):

b=sqrt12

OpenStudy (anonymous):

not anymore, just place if to the formula

OpenStudy (darkbluechocobo):

\[\frac{ x^2 }{ 4 }-\frac{ y^2 }{ 12 }=1\]

OpenStudy (anonymous):

\[\frac{ y^2 }{ (2)^2 }-\frac{ x^2 }{ 12}=1\]

OpenStudy (anonymous):

yes you got it :D

OpenStudy (darkbluechocobo):

Thank you :D

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