Question

Graph -x^2+6x-9=0

Answer 1

you mean graph \(y=-x^2+6x-9\) ?

Answer 2

you want to graph the curve, not just some xintercepts

Answer 3

Yes i want both graph and x,y intercepts

Answer 4

\(y=-x^2+6x-9\)
\(y=-(x^2-6x+9)\)
\(y=-(x^2-3x-3x+9)\)
\(y=-(x(x-3)-3(x-3))\)
\(y=-(x-3)(x-3)\)
\(y=-(x-3)^2\)
this is a parabola (that opens down).

in general:
\(y=\color{red}{a}(x-\color{green}{h})^2+\color{blue}{k}\)
is the form of an opening up (when a>0) parabola or opening down (when a<0) parabola, centered at \((h,k)\).

In your case:
\(y=\color{red}{(-1)}(x-\color{green}{3})^2+\color{blue}{0}\)

Answer 5

to find the y-intercepts, set x=0 and solve for y.

to find the x-intercepts, set y=0 and solve for x.

Answer 6

Thank you

Answer 7

you welcome