find the domain of the given function.
f(x)=sqrt(x+3)/(x+8)(x-2)
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OpenStudy (anonymous):
is all that mess under the radical?
OpenStudy (chris215):
\[f(x)=\sqrt{x+3}/(x+8)(x-2)\]
OpenStudy (anonymous):
only the numerator is under the radical?
OpenStudy (anonymous):
do u go to connecitons 8grade
OpenStudy (chris215):
yes @satellite73
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OpenStudy (anonymous):
no i am in ninth grade
OpenStudy (chris215):
and no @ddds
OpenStudy (anonymous):
ok so first lets take care of the numerator
since you cannot take the square root of a negative number, solve
\[x+3\geq 0\] in one step
OpenStudy (anonymous):
you got that?
OpenStudy (chris215):
x\[x \ge -3\]
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OpenStudy (anonymous):
yeah so that is a start
OpenStudy (anonymous):
then set the denominator equal to zero and solve, because you cannot divide by zero
i.e solve
\[(x+8)(x-2)=0\] what do you get?
OpenStudy (chris215):
x=2,-8?
OpenStudy (anonymous):
right so those values are out
but you can ignore the \(-8\) because we already know \(x\) has to be greater than or equal to \(-3\)
now we also know it cannot be 2
OpenStudy (anonymous):
then i guess the question is, how do you write that?
are you supposed to answer in interval notation? in words? as an inequality?
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OpenStudy (chris215):
OpenStudy (chris215):
those are my choices
OpenStudy (chris215):
so would it be the second to last?
OpenStudy (anonymous):
yeah it is always C
OpenStudy (chris215):
ok thanks so much :)
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