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Mathematics 17 Online
OpenStudy (anonymous):

Piecewise function help!!?

OpenStudy (anonymous):

http://gyazo.com/5a0be0f54375e895c1c46c4325fc0159

OpenStudy (anonymous):

^^ question is in link

OpenStudy (anonymous):

-4 and 4 are not equal to 1, use the top rule

OpenStudy (anonymous):

1 is equal to 1, so \(f(1)=2\)

OpenStudy (anonymous):

im still so confused, i do not remember learning this

OpenStudy (anonymous):

lol maybe you are supposed to be learning this now! it is not like you are born knowing it

OpenStudy (anonymous):

the way you read the function is this \(f(x)=\frac{1}{2}x+2\) if x is not equal to 1 so for any number not equal to 1, use that rule for example \[f(4)=\frac{1}{2}\times 4+2=2+2=4\]

OpenStudy (anonymous):

\[f(-4)=\frac{1}{2}\times (-4)+2\] etc

OpenStudy (anonymous):

the only time you do not use that rule is if \(x=1\) because you are told that \(f(1)=2\)

OpenStudy (anonymous):

so for my answer for f(-4) i need to do 1/2 x(-4)+2??

OpenStudy (anonymous):

yes exactly

OpenStudy (anonymous):

and as for the rest im not to sure, its like overwhelming looking at it lol

OpenStudy (anonymous):

there is no rest you are only asked for three numbers \[f(-4)\] which you know how to compute \[f(1)\] which you are told is \(2\) and \[f(4)\] which we already computed

OpenStudy (anonymous):

so f(1)= 1/2 (-1)+2?

OpenStudy (anonymous):

wait no, f(1)=1/2 (2)+2?

OpenStudy (anonymous):

lets go slow

OpenStudy (anonymous):

you see on the bottom row, it says " 2 if x = 1" right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that is another way of saying \[f(1)=2\] i.e. it is 2 if x is 1

OpenStudy (anonymous):

so do i just plug it in like the equation we did for -4??

OpenStudy (anonymous):

no you do not you say \(f(1)=2\))

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

any other number you would plug in, but not 1

OpenStudy (anonymous):

so f(-4) =0 f(1)=2 f(4)=4?

OpenStudy (anonymous):

i got this one thanks. the next one looks more complicated though lol

OpenStudy (anonymous):

post it i can help

OpenStudy (anonymous):

http://gyazo.com/35cb71d59b6a6a71ae2af3c9e3204d15 ^^ okay here it is @satellite73

OpenStudy (anonymous):

yeah it is more complicated, but it is not complicated if you know how to read it for \(f(-2)\) yhou have to figure out which rule to use out of a possible 4 it could be -2,-1,0 or 1

OpenStudy (anonymous):

the question is, which one, and you do that be figuring out which inequality \(-2\) satisfies (fits)

OpenStudy (anonymous):

evidently it fits the top inequality \(-2\leq x<-1\) so use the top one, i.e. \[f(-2)=-2\]

OpenStudy (anonymous):

of the four posslbe numbers, what do you think \(f(-1.75)\) is? which inequality does \(-1.75\) satisfy ?

OpenStudy (anonymous):

the third one? 0?

OpenStudy (anonymous):

hmm no

OpenStudy (anonymous):

\[0\leq -1.75<1\]is defintely not true

OpenStudy (anonymous):

oops i forgot the negative part!

OpenStudy (anonymous):

lol yeah that minus sign if for real try again?

OpenStudy (anonymous):

i think the second one -1 but isnt -1 bigger then -1.75? :c

OpenStudy (anonymous):

yes -1 is bigger, so no, not the second one

OpenStudy (anonymous):

all thats left is 1

OpenStudy (anonymous):

unless u can reuse the top equation..

OpenStudy (anonymous):

yea \[-2\leq -1.75<-1\] is true

OpenStudy (anonymous):

of course you can reuse it you did not use it up

OpenStudy (anonymous):

oh gosh i feel dumb now lol i thought it was done cuz we already plugged it in ok

OpenStudy (anonymous):

so that makes \[f(-1.75)=2\] use the top one

OpenStudy (anonymous):

one more to go, i bet you can do it

OpenStudy (anonymous):

1 the last one

OpenStudy (anonymous):

oops typo

OpenStudy (anonymous):

i meant \[f(-1.75)=-2\] sorry

OpenStudy (anonymous):

yeah you are right, \[f(1)=1\]

OpenStudy (anonymous):

not so hard once you know how to read it right?

OpenStudy (anonymous):

woohoo! thanks! i only have 1 more of these questions to go

OpenStudy (anonymous):

still want help or you got it?

OpenStudy (anonymous):

might need a litle help

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

I wish there was a way to give you like 10 million medals! lol

OpenStudy (anonymous):

http://gyazo.com/e18648acb9277fe638038ae9c3d7b9a9

OpenStudy (anonymous):

for the first one is it -1/2*(1)+2??

OpenStudy (anonymous):

no

OpenStudy (anonymous):

oh man:/ ookay ya i need help

OpenStudy (anonymous):

which inequality does 1 satisfy ?

OpenStudy (anonymous):

top, middle or bottom?

OpenStudy (anonymous):

middle

OpenStudy (anonymous):

yes replace \(x\) by \(1\) in the middle formula, you can do it in your head

OpenStudy (anonymous):

1

OpenStudy (anonymous):

g(1)=1?

OpenStudy (anonymous):

hmmm no

OpenStudy (anonymous):

\[g(1)\] use the middle rule \[f(x)=-(x-1)^2+3\]

OpenStudy (anonymous):

not to be mean, but where did you get the one from? you need \[g(1)=-(1-1)^2+3\] which is not one for sure

OpenStudy (anonymous):

i honestly have no idea im tired, its 3?

OpenStudy (anonymous):

yeah 3

OpenStudy (anonymous):

and then for the next one it fits best in the middle one agIN I believe

OpenStudy (anonymous):

let me look again

OpenStudy (anonymous):

yes you are right

OpenStudy (anonymous):

so 2?

OpenStudy (anonymous):

and thee last one goes in the bottm inequilty so it equals 4? ?

OpenStudy (anonymous):

yes 2

OpenStudy (anonymous):

yes 4 for the last one

OpenStudy (anonymous):

yay thank you so much!

OpenStudy (anonymous):

yw hope you learned something even though you did not know it before

OpenStudy (anonymous):

i did your a good teacher lol

OpenStudy (anonymous):

thanks!

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