im still so confused, i do not remember learning this
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OpenStudy (anonymous):
lol maybe you are supposed to be learning this now! it is not like you are born knowing it
OpenStudy (anonymous):
the way you read the function is this
\(f(x)=\frac{1}{2}x+2\) if x is not equal to 1
so for any number not equal to 1, use that rule
for example
\[f(4)=\frac{1}{2}\times 4+2=2+2=4\]
OpenStudy (anonymous):
\[f(-4)=\frac{1}{2}\times (-4)+2\] etc
OpenStudy (anonymous):
the only time you do not use that rule is if \(x=1\) because you are told that \(f(1)=2\)
OpenStudy (anonymous):
so for my answer for f(-4) i need to do 1/2 x(-4)+2??
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OpenStudy (anonymous):
yes exactly
OpenStudy (anonymous):
and as for the rest im not to sure, its like overwhelming looking at it lol
OpenStudy (anonymous):
there is no rest
you are only asked for three numbers
\[f(-4)\] which you know how to compute
\[f(1)\] which you are told is \(2\) and
\[f(4)\] which we already computed
OpenStudy (anonymous):
so f(1)= 1/2 (-1)+2?
OpenStudy (anonymous):
wait no, f(1)=1/2 (2)+2?
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OpenStudy (anonymous):
lets go slow
OpenStudy (anonymous):
you see on the bottom row, it says " 2 if x = 1" right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
that is another way of saying \[f(1)=2\] i.e. it is 2 if x is 1
OpenStudy (anonymous):
so do i just plug it in like the equation we did for -4??
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OpenStudy (anonymous):
no you do not
you say \(f(1)=2\))
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
any other number you would plug in, but not 1
OpenStudy (anonymous):
so f(-4) =0 f(1)=2 f(4)=4?
OpenStudy (anonymous):
i got this one thanks. the next one looks more complicated though lol
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yeah it is more complicated, but it is not complicated if you know how to read it
for \(f(-2)\) yhou have to figure out which rule to use out of a possible 4
it could be -2,-1,0 or 1
OpenStudy (anonymous):
the question is, which one, and you do that be figuring out which inequality \(-2\) satisfies (fits)
OpenStudy (anonymous):
evidently it fits the top inequality \(-2\leq x<-1\) so use the top one, i.e.
\[f(-2)=-2\]
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OpenStudy (anonymous):
of the four posslbe numbers, what do you think \(f(-1.75)\) is? which inequality does \(-1.75\) satisfy ?
OpenStudy (anonymous):
the third one? 0?
OpenStudy (anonymous):
hmm no
OpenStudy (anonymous):
\[0\leq -1.75<1\]is defintely not true
OpenStudy (anonymous):
oops i forgot the negative part!
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OpenStudy (anonymous):
lol yeah that minus sign if for real
try again?
OpenStudy (anonymous):
i think the second one -1 but isnt -1 bigger then -1.75? :c
OpenStudy (anonymous):
yes -1 is bigger, so no, not the second one
OpenStudy (anonymous):
all thats left is 1
OpenStudy (anonymous):
unless u can reuse the top equation..
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OpenStudy (anonymous):
yea
\[-2\leq -1.75<-1\] is true
OpenStudy (anonymous):
of course you can reuse it
you did not use it up
OpenStudy (anonymous):
oh gosh i feel dumb now lol i thought it was done cuz we already plugged it in ok
OpenStudy (anonymous):
so that makes
\[f(-1.75)=2\] use the top one
OpenStudy (anonymous):
one more to go, i bet you can do it
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OpenStudy (anonymous):
1 the last one
OpenStudy (anonymous):
oops typo
OpenStudy (anonymous):
i meant
\[f(-1.75)=-2\] sorry
OpenStudy (anonymous):
yeah you are right,
\[f(1)=1\]
OpenStudy (anonymous):
not so hard once you know how to read it right?
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OpenStudy (anonymous):
woohoo! thanks! i only have 1 more of these questions to go
OpenStudy (anonymous):
still want help or you got it?
OpenStudy (anonymous):
might need a litle help
OpenStudy (anonymous):
kk
OpenStudy (anonymous):
I wish there was a way to give you like 10 million medals! lol
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