Question

Super confused? Are parallel functions inverse functions? Graph attached

Answer 1

its really throwing me off because there's no curves, it's really hard to tell if it's an inverse function or not...

Answer 2

those functions are not parallel

Answer 3

So they're not inverse functions, I'm assuming as well

Answer 4

those lines are not parallel *

Answer 5

you can test whether they are inverse

Answer 6

how?

Answer 7

check whether it is true that
g(f(x)) = x
or
f(g(x)) = x

Answer 8

I don't know what to plug in for that

Answer 9

It's strange, the two g(x)'s don't match.
Did you write in the one in the `plot` box?

Answer 10

f(x) = 3x+2
g(x) = (x-2)/3

Answer 11

@perl I had typed graph, is there a difference between graph and plot?

Answer 12

you need parentheses around g(x) = `(x-2) / 3 `

Answer 13

ahhh I see the error now

Answer 14

one moment

Answer 15

Here's how it properly looks @perl

Answer 16

...I'm still really not sure if this is an inverse function or not, still leaning towards its not though

Answer 17

@zepdrix what do I need to do? I didn't understand perl's explanation

Answer 18

You could try do a composition as he suggested, I think you need a better understanding of functions to do that though.

I would recommend starting with f, and applying your inverse steps and then see if it turns into g.

Sec, I'll explain.

Answer 19

\[\Large\rm f(x)=3x+2\]We start by calling f(x) y for simplicity,\[\Large\rm y=3x+2\]Switch your y and x's.\[\Large\rm x=3y+2\]Now THIS y represents the inverse function.
Solve for this y, get it alone.
Do you understand the steps to do so? how to solve for y?

Answer 20

y-2/3=x?

Answer 21

It's hard to tell with the way you wrote it :OC
Did you mean \(\Large\rm \frac{y-2}{3}\) or \(\Large\rm y-\frac{2}{3}\) ?

Answer 22

the first one

Answer 23

Ok good! :)
But notice I switched the x's and y's.
You should have ended up with \(\Large\rm y=\frac{x-2}{3}\)

Answer 24

and that looks like the second function...so they ARE inverse of each other?

Answer 25

Yesss good job! :)

Answer 26

THANKS SO MUCH