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Mathematics 6 Online
OpenStudy (aaronandyson):

The angle of elevation of the top of an unfinished tower at a point is 80 m from the base is 30 degrees.How much higher must be the tower to be raised so that its angle of elevation at the same point be 60 degrees?

OpenStudy (aaronandyson):

@phi

OpenStudy (anonymous):

I'd just like to confirm, but the base length will not be changing right?

OpenStudy (aaronandyson):

I'm concerned about that also lol

OpenStudy (aaronandyson):

In all probability It shouldn't change.

OpenStudy (anonymous):

Because if it doesn't then I have it figured it out

OpenStudy (aaronandyson):

Help me then?

OpenStudy (anonymous):

Sure. The whole way of doing this problem goes on the basis of the properties of 30-60-90 triangles. The original triangle will have a base of \[80\sqrt{3}\]

OpenStudy (aaronandyson):

HA! They had told to take sqrt3 as 1.73 I got the base length to be as 138.4m

OpenStudy (anonymous):

Well if you have a 30-60-90 triangle and the 30 degrees side is 80, the other side will just be that times sqrt3. You could write it as the decimal form but it's a lot neater otherwise. So we are going to have two pieces of info going into the second triangle. That the base is \[80\sqrt{3}\] and that the new angle opposite the wall will be 60

OpenStudy (anonymous):

|dw:1431698120231:dw| Now just use the same properties of a 30-60-90 triangle with the base as the 30 now and the wall as the 60.

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