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Using the given zero, find all other zeros of f(x). -2i is a zero of f(x) = x4 - 45x2 - 196
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so +2i will also be a zero of f(x)
2i is one of the other zero as complex zeros of a real polynomial always come in conjugate pairs. Complex conjugate of a+bi is a-bi.
so is it 2i,7,-7??
Because 2i is a zero and -2i is a zero, the f(x) is divisible \((x-2i)(x+2i)=x^2+4\). Divide f(x) by \(x^2+4\) to yield a quadratic. Solve that quadratic.
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