Question

if 75.0g of silderite ore is heated with an excess of oxygen, 45.0 g of ferric oxide is produced.
4FeCO3 + O2 -> 2Fe2O3 + 4CO2

Answer 1

about 90%, do you want me to explain

Answer 2

1.) our reagent FeCO3-
mass-116, 0.65(75g/116g/moles)

2.) 1moles Fe2O3 for every 2mole FeCO3
Fe2O3=.325moles

3.) Get both mass of Fe2CO3 and FeCO3
45, 160 grams

4.) 45/160grams*100=about 90%