Question

Find the measure of arc DC if measure of arc BC is equal to 51° and angle A measures 21

Answer 1

@Michele_Laino

Answer 2

what do you think

Answer 3

i think its 93

Answer 4

close

Answer 5

then it must be 72

Answer 6

@Michele_Laino 21 = (51-x)/2

Answer 7

that would be the equation to solve for the measure of DC

Answer 8

hint:
your problem can be modeled by the subsequent drawing:

Answer 9

where O is the center of your circumference

Answer 10

now what is the measure od the angle <OQD?

Answer 11

i havent done angles in a long time. this question came out from the blue

Answer 12

hint:
angles OQD and AQC are vertical angles

Answer 13

we have that the measure of angle OQD is 69 degrees, so the mesure of the angle OQB is 180-69=...?

Answer 14

111 i meant

Answer 15

that's right!

Answer 16

so the measure of the angle OBQ, is:
180-(51+111)=...?

Answer 17

18

Answer 18

that's right!

Answer 19

your right

Answer 20

Now also the measure of angle ODQ is 18 degrees, since the triangle BOD, is an isosceles triangle

Answer 21

so the requaeste measure x, have to checks this equality:
x+18+69=180,
where x is the measure of the angle COD.
What is x?

Answer 22

oops..the requested* measure

Answer 23

x = 93

Answer 24

That's right!
sorry for my grammar errors

Answer 25

so, what is the right option?

Answer 26

93 would be correct?

Answer 27

yes! It is correct!

Answer 28

@Michele_Laino last ones

Answer 29

I'm trying to solve your exercise, please wait

Answer 30

Hint:
2 events are mutually exclusive, when the occurring of one excludes the occurring of the other

Answer 31

so, if I draw a king, I can not draw a queen, and vice versa

Answer 32

the event king of heart exists, namely it can occur

Answer 33

and a club is a black card

Answer 34

so the answer would be D ?

Answer 35

a face card means a Queen, or a King or a Jack, I think

Answer 36

so all of them are connected somehow

Answer 37

I think that the in the first option there are two events mutually exclusive

Answer 38

namely, a card can be a King, or can be a Queen

Answer 39

hmm, im confused. i cant agree on which is the right option

Answer 40

why?

Answer 41

which one would be the correct option! A?

Answer 42

yes! I think so!

Answer 43

please wait a moment I will be back between 10 minutes

Answer 44

have a couple minutes left to submit the assaignment. mind helping with the last question. @Michele_Laino . i choose A as the answer. is that correct

Answer 45

I'm sorry, since we have to know something of genetics here

Answer 46

@Michele_Laino its probablity. not anything about gentiics. can you take a look at the chart and it will explain it a little

Answer 47

ok! please wait a moment I'm trying to solve your exercise, and then I will explane my solution

Answer 48

explain*

Answer 49

here is my reasoning:
1) the probability to pick a person of group A is: 264/311= 0.8488

2) the probability to pick a person with a Rh positive is: 264/629= 0.4197

3) the probability to pick a person with group A "AND" Rh positive, is: 264/740=0.3567

So the requested probability is given by the subsequent computation:
(0.8488+0.4197)-0.3567=...?
I have used this formula
P(A union B)=P(A)+P(B)-P(A intersection B)
where A, and B are two generic events