Question

Water at a pressure of12.50 x 10^2 pa flows through a horizontal pipe at a speed of 2.50 m/ s. The pipe narrows to one - sixth it's original diameter

Answer 1

@ghuczek

Answer 2

you haven't actually asked a question and you probably want to dig out Bernoulli's fluid flow equation when you do :p
\[P + \rho gh + \frac{1}{2} \rho v^2 = constant\]

Answer 3

Hint:
Also, you have to consider the subsequent equation (continuity law)
\[\Large {A_1}{v_1} = {A_2}{v_2}\]
where A_1 A_2 are the areas of two cross sections of the pipe, and v_1 and v_2 are the corresponding velocities of the flow