I'm stuck on this problem, can someone please help?

Question

anonymous · Answer

2x+y=15
(x-2)^2 + (y-1)^2 = 25

anonymous · Answer

I keep getting x = 5/2

anonymous · Answer

but i don't know if I correct

anonymous · Answer

@freckles You mind helping?

anonymous · Answer

@welshfella  you mind helping?

anonymous · Answer

@Rubyjadeluv  you mind helping?

welshfella · Answer

from  first equation y = 15 - 2x
so substitute this for y in second equation 
did you do it this way?

anonymous · Answer

No. This is what I did


(x-2)^2 + (y-1)^2 = 25

x^2-4x+4+y^2-2y+1= 25

anonymous · Answer

want me to continue?

welshfella · Answer

ok  so the next was the substitution ?

anonymous · Answer

(x-2)^2 + (y-1)^2 = 25

x^2-4x+4+y^2-2y+1= 25

x^2 - 4x + y^2 - 2y +5 = 25

x^2 - 4x + y^2 - 2y = 20

this is where I get stuck

x^2 + 0x + y^2 + 0y = 20

x^2 + 4x + y^2 + 2y = 20
----------------------
        4x       +      2y   =  0

welshfella · Answer

hmmm what was the question   solve for x and y ?

anonymous · Answer

"Solve the following system of two circles by finding the intersection points
algebraically."

welshfella · Answer

??   well 2x + y = 15 is a straight line not a circle.

anonymous · Answer

ohh I see what i'm doing wrong... I'm using the wrong formula ._.

anonymous · Answer

sorry for wasting your time

anonymous · Answer

thanks for trying to help.

welshfella · Answer

thats ok