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Solve for x 150=50e^7x
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a. x=ln(3)-7 b. x=l/e c. x=ln(3)/7 d. x=ln(150)/79(ln)(50)
I think its c, right?
same process as before divide both side by 50 then take the logs and use the rule for powers
Okay I divided by 50 and got 3=e^7x now we have to use ln because e is the base of a natural log.
I get confused when using the laws of powers.
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especially with the "e^7x"
you need to recognize \[\ln(e^{7x}) = 7x\] when the base of the log and the base of the exponent are the same it becomes 1 to explain using log laws its \[e^7x = \ln(e^{7x}) = 7x \times \ln(e) = 7x \times 1\]
The options are x=ln(3)-7 x=l/e x=ln(3)/7 x=ln(150)/7(ln(50))
@campbell_st
so then would it be x=ln(3)/7
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its would be
okay cool.
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