Perform the indicated operation. https://clackamasweb.owschools.com/media/g_ima01_2014/2/136.gif
https://clackamasweb.owschools.com/media/g_ima01_2014/2/yplus5_yminus5.gif https://clackamasweb.owschools.com/media/g_ima01_2014/2/negyplus5_yminus5.gif https://clackamasweb.owschools.com/media/g_ima01_2014/2/yminus5_5minusy.gif
@wio
@TheRaggedyDoctor
\(\dfrac{y}{y-5}+\dfrac{5}{5-y}\) \(\dfrac{(5-y)}{(5-y)}\dfrac{y}{y-5}+\dfrac{(y-5)}{(y-5)}\dfrac{5}{5-y}\) \(=\frac{5y-y^2+5y-25}{(5-y)(y-5)}=\frac{-y^2+10y-25}{(y-5)(5-y)}=\frac{-y^2+5y+5y-25}{(y-5)(5-y)} \\ = \frac{-y(y-5)+5(y-5)}{(y-5)(5-y)}=\frac{(y-5)(5-y)}{(y-5)(5-y)}=1\)
I dont have 1 in my choices
your choices are wrong
http://www.wolframalpha.com/input/?i=%5Cdfrac%7By%7D%7By-5%7D%2B%5Cdfrac%7B5%7D%7B5-y%7D+%3D+1
Another way to do it \[\Large \frac{y}{y-5}+\frac{5}{5-y}\] \[\Large \frac{y}{y-5}+\frac{5}{-1(-5+y)}\] \[\Large \frac{y}{y-5}-\frac{5}{y-5}\] \[\Large \frac{y-5}{y-5}\] \[\Large 1\] So \(\Large \frac{y}{y-5}+\frac{5}{5-y}\) simplifies to \(\Large 1\)
thank you
his is much more clever ;) as always
both of our answers should say that this is true as long as \(y\ne 5\)
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