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Mathematics 18 Online
OpenStudy (anonymous):

Perform the indicated operation. https://clackamasweb.owschools.com/media/g_ima01_2014/2/136.gif

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

@TheRaggedyDoctor

OpenStudy (zzr0ck3r):

\(\dfrac{y}{y-5}+\dfrac{5}{5-y}\) \(\dfrac{(5-y)}{(5-y)}\dfrac{y}{y-5}+\dfrac{(y-5)}{(y-5)}\dfrac{5}{5-y}\) \(=\frac{5y-y^2+5y-25}{(5-y)(y-5)}=\frac{-y^2+10y-25}{(y-5)(5-y)}=\frac{-y^2+5y+5y-25}{(y-5)(5-y)} \\ = \frac{-y(y-5)+5(y-5)}{(y-5)(5-y)}=\frac{(y-5)(5-y)}{(y-5)(5-y)}=1\)

OpenStudy (anonymous):

I dont have 1 in my choices

OpenStudy (zzr0ck3r):

your choices are wrong

jimthompson5910 (jim_thompson5910):

Another way to do it \[\Large \frac{y}{y-5}+\frac{5}{5-y}\] \[\Large \frac{y}{y-5}+\frac{5}{-1(-5+y)}\] \[\Large \frac{y}{y-5}-\frac{5}{y-5}\] \[\Large \frac{y-5}{y-5}\] \[\Large 1\] So \(\Large \frac{y}{y-5}+\frac{5}{5-y}\) simplifies to \(\Large 1\)

OpenStudy (anonymous):

thank you

OpenStudy (zzr0ck3r):

his is much more clever ;) as always

OpenStudy (zzr0ck3r):

both of our answers should say that this is true as long as \(y\ne 5\)

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