Can you help me find the polar coordinates of each rectangular coordinates (4,0) (0,3) (2,2)
notice, they're just x,y coordinate values thus, plot them in a cartesian plane grid get the distance, that'd be "r" get the angle, that'd be \(\theta\) then plug the values for the polar coordinates using that :)
usually you'd need to use the tangent function to get the angle but in this case, is too simple
so will the first one be (4,0 degrees)
well.... plot here |dw:1431733421540:dw|
|dw:1431732726359:dw|
yeap... so r = 4 and angle is 0 so 4, 0 is the polar
what equation would I use
|dw:1431733663462:dw| notice, the angle is 90 degrees and the distance is 3
hmm what equation? for.... well.. that was the 1st one, (4,0) in rectangular is the same in polar
ok Next one would be (3,90 degrees)
0, 3 has an r = 3, and an angle of \(\frac{\pi }{2}\)
yeap or \(\bf (3,\frac{\pi }{2})\)
next one would be (2sqrt(2), 45 degrees)
now... 2.2.... well.. hmmm yeap, that's correct \(\bf r=\sqrt{x^2+y^2}\implies r=\sqrt{2^2+2^2}\implies r=\sqrt{8}\implies r=2\sqrt{2} \\ \quad \\ \theta=tan^{-1}\left( \cfrac{y}{x} \right)\implies \theta=tan^{-1}\left( \cfrac{\cancel{2}}{\cancel{2}} \right)\)
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