integral of:
\[\int\limits_{?}^{?}(x+2)^2/(x^2+1)\]
i think you have to multply out
So integral of (x^2+4x+4)/(x^2+1) ? I tried that but idk what to do from there
i would try \[\frac{x^2+1+4x+3}{x^2+1}=1+\frac{4x+3}{x^2+1}\] maybe that will help
i suck at these so maybe there is a snappier way you are going to have to divide for sure, because as you see you get a 1 there the next part i am less sure about
Can't I solve the integral of (4x+3)/(x^2+1) using that rule I forgot... Ax+B = ...
partial fractions*
no \(x^2+1\) does not factor, no partial fractions for this one
break apart again to get a log and a arctangent i think
What do you mean by break apart?
ok you good to here \[\frac{x^2+1+4x+3}{x^2+1}=1+\frac{4x+3}{x^2+1}\]
Yup I am
then \[1+\frac{4x}{x^2+1}+\frac{3}{x^2+1}\]
ohhh that's really smart. I see how to solve it now
first term gives \(x\) last term is arctangent middle one is a simple u - sub
oh ok said too much good luck
Thanks so much for your help!
yw
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