Convert polar eq. to rectangular cos2(Theta)=-1
@zepdrix
@sdfgsdfgs
@rvc
@perl
Is that a square on the cosine? :)
Nope, it's\[\cos2(\theta)=-1\]
Recall your Double Angle Formula for Cosine? :)
\[\cos^2(\theta)-\sin^2(\theta)=-1\]
Wait, we're going to rectangular? 0_o but no r? Hmm interesting lol
yeah that's what's weird! xD I've tried multiplying r in but it gets pretty sketchy.
How bout we... multiply both by r^2
\[\Large\rm (r \sin \theta)^2-(r \cos \theta)^2=1\]I combined a few steps into one here, ok with this? :o
Crappp my game is starting >.<
ai, do you need to go?
Woops typo,\[\Large\rm (r \sin \theta)^2-(r \cos \theta)^2=r^2\]
Yah :c Do you see how I got here? Can you continue from there maybe? :3
Hm, I'm not sure. But i'll work it out. You can go! thanks :)
ok ill come back later if needed c:
okies. but the r on the right side would be negative, yeah?
@alekos
This is the question $$\Large \cos(2\theta) = -1$$
yep
We can use trig substitution $$ \Large{ \cos(2\theta) = -1 \\ 2\cos^2\theta -1 = -1 } $$
Okay, sounds good..
\[2\cos^2(\theta)=0\] simplify?
correct
We can use trig substitution $$ \Large{ \cos(2\theta) = -1 \\ 2\cos^2\theta -1 = -1 \\ 2\cos^2\theta = 0 \\ \cos^2\theta = 0 \\ \cos\theta = 0 \\ \theta = \arccos(0) \\ \theta = \frac{\pi }{2} } $$ now it is true that in polar to rectangular theta = arctan(y/x)
actually that is the y axis, if you graph it
so the rectangular equation is x = 0
oo yes this makes sense.
|dw:1431760535899:dw|
Join our real-time social learning platform and learn together with your friends!