The blackbody curve for a star named Beta is shown below. What is the surface temperature of this star rounded to the nearest whole number?
https://clackamasweb.owschools.com/media/g_ipc_2014/11/blackbody_beta.gif

14,500 K
58,000 K
6,897 K
200 K

Question

The blackbody curve for a star named Beta is shown below. What is the surface temperature of this star rounded to the nearest whole number?
https://clackamasweb.owschools.com/media/g_ipc_2014/11/blackbody_beta.gif


14,500 K
58,000 K
6,897 K
200 K

anonymous · Answer

@UnkleRhaukus

unklerhaukus · Answer

is this an application Wien's displacement law

anonymous · Answer

i think so

anonymous · Answer

https://clackamasweb.owschools.com/media/g_ipc_2014/11/ipc_u11_q10_a.gif

unklerhaukus · Answer

Remember, you found the wavelength of maximum intensity (of the star beta), to be:$$\lambda_\text{peak}=200\,[\text{nm}]$$

unklerhaukus · Answer

so, plug it into the formula, , , and simplify

unklerhaukus · Answer

the nanometers; nm, will cancel . . .

unklerhaukus · Answer

@hhelpplzzzz

anonymous · Answer

thank you:)