Question

The sum of the squares of two consecutive natural numbers is 41.Find the number
@sepeario
@unklerhaukus

Answer 1

\[x ^{2}+(x+1)^{2}\]

Answer 2

Of course you could substitute values into the equation by guess and check.

Answer 3

Because there are so little square numbers under 40: 1=1, 2=4, 3=9, 4=16, 5=25, 6=36; and from these numbers there is one outstanding solution, 4 squared + 5 squared.

Answer 4

You can also use the quadratic formula for this.

Answer 5

4 &5 ?

Answer 6

I got this
x^2 + x - 20 = 0

Answer 7

4 & - 5?

Answer 8

Ok. Using quadratic formula,

Answer 9

Of course that would be a bit far for this kind of question.