A company estimates its total profit (profit = total revenue minus total cost) as P(x) = 2x^5 − 3x^4 − 5x^2 − 2, where P is in thousands of dollars and x is the number of years elapsed since the company was founded. How many times can the total profit become exactly zero? Hint: Use Descartes's rule of signs.
2 or 0 5 or 3 or 1 3 or 1 1
@Michele_Laino @posingocean
@Nnesha
we have to find the roots of the polynomial P(x)
Okay, let me do that real quick.
About 2.1?
I'm computing...
I got this computation: if we set x=2, we have: P(2)=-6 <0 whereas, if we set x=3, we get: P(3)=176, please check those numbers Now, since every polynomial is a continuous function, then our polynomial assumes all values between -6 and 176, so it will assume the value 0, then will exist a x-coordinate, say x_0, between 2, and 3, such that P(x_0)=0
Oh.. well I just Mathway and the root is x=2.111219. But if I do the rational root test then I get + or - 1, + or - 0.5 and + or - 2
please look at this drawing:
Okay, I did... I'm sorry I still don't really understand what I'm supposed to find.
I think that the total profit P(x) is equal to zero exactly only one time, between, say the second year and the third year
Oh, okay. But the options don't have a 2-3. The options are posted in the comments.
I think the last one, namely 1
That's what I was thinking too. Thank you :)
Thank you! :)
Join our real-time social learning platform and learn together with your friends!