Question

What is the electric force between a +3 µC point charge and a +6 µC point charge if they are separated by a distance of 0.75 m? (µC = 1.0 × 10^–6 C)

***How do I show the work for this? Thank you!!

Answer 1

here we have to apply the Coulomb law, namely the force of interaction, which is a repulsive force, is given by the subsequent formula:
\[\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}\]

Answer 2

:)

Answer 3

i'm not sure what do i sub in? :/

Answer 4

where K=9*10^9 Q_1, Q_2 are the two electric charges, and d is their separation. So substituting, we have:
\[\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}} = 9 \times {10^9}\frac{{3 \times {{10}^{ - 6}} \times 6 \times {{10}^{ - 6}}}}{{{{\left( {0.75} \right)}^2}}}\]

Answer 5

ok! how would i insert that into my calc?

would i get 0.288?

i do not know if i inserted it correctly? :/

Answer 6

that's right! The correct result is a force whose modulus is:
F=0.288 Newton

Answer 7

oh yay!! :) is that the answer? or is there more? or is 0.288 newton the answer? that is the electrical force?

Answer 8

yes! We can draw that force as below:

Answer 9

ooh yay!! so we are done?

Answer 10

yes! we have finished!

Answer 11

yay!! thank you1!

Answer 12

thank you! :)